SQL 比较一个集合是否在另一个集合里存在的方法分享
实现代码如下: DECLARE @c INT DECLARE @c2 INT SELECT @c = COUNT(1) FROM dbo.SplitToTable('1|2|3|4', '|') SELECT @c2=COUNT(1) FROM dbo.SplitToTable('1|2|3|4',
实现代码如下: DECLARE @c INT DECLARE @c2 INT SELECT @c = COUNT(1) FROM dbo.SplitToTable('1|2|3|4', '|') SELECT @c2=COUNT(1) FROM dbo.SplitToTable('1|2|3|4',
:指定参数 实现代码如下: public DataTable TodayToTable(int userId) { return userId > 0 ? V_CN_TASK_VALID_SCORING_TODAY.QueryTable(condition: " WHERE 承接者Id = "
第一句:SELECT * INTO [ToTable] FROM [FromTable] 第二句:INSERT INTO [ToTable] ([fild_One],[fild_Two]) SELECT [fild_One], 8 FROM [FromTable] 以上两句都是将 [FromTabl