SQL语句查询数据库中重复记录的个数
实现代码如下:select a,b,c,count(*) from (select c.a,c.b,c.c from test c) having count(*) >= 2 group by a,b,c 或者 实现代码如下:select zdbh,tdzl,zdmj,count(*) fro
实现代码如下:select a,b,c,count(*) from (select c.a,c.b,c.c from test c) having count(*) >= 2 group by a,b,c 或者 实现代码如下:select zdbh,tdzl,zdmj,count(*) fro
先写一个数据库统计函数 实现代码如下: public static int Count(string cityName) { string cmdText = ""; SqlConnection conn = new SqlConnection(DBH.DBA); SqlCommand cmd =
实现代码如下: link = @$conn($dbhost, $dbuser, $dbpw, 1)) { $halt } else { if($this->version() > '4.1') { global $charset, $dbcharset; $dbcharset = $d
"; echo "IDName"; while($row = mysql_fetch_row($rs)) echo "$row[0]$row[1]"; /* 定义量变(数组)row,并利用while循环,把数据一一写出来.函数mysql_fetch_row()的意思是:将查询结果$rs单列拆
1,php连接数据库 2.php读取数据库中,某一字段值 \n", mysql_result($result,3,"UserName")); printf("密码: %s\n", mysql_result($result,3,"UserPass")); ?> 3,php插入某一条数据 4,
NULL值的判断 $t{type1id} = $$pref{dbh}->selectrow_array("SELECT type1id FROM enq1 WHERE id = 3"); if ( $t{type1id} == 0 ) { print "Type1id is NULL\n";
从一个不错的留言本弄的mysql数据库操作类,初学php的朋友可以参考下show('Can not connect to MySQL server'); return false; } if($dbname) { $this->select_db($dbname); } if($this-&g