select count(point_id) as today_sum from point where datediff(d,point_date,getdate())=0
关键语句：
datediff(d,point_date,getdate())=0
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select count(point_id) as today_sum from point where datediff(d,point_date,getdate())=0
关键语句：
datediff(d,point_date,getdate())=0